40行JavaScript代码实现的3D旋转魔方动画效果

JS1K是JavaScript编程竞赛——参加竞赛的规则很简单，脚本必须小于1K，竞赛网站将开始也只是为了娱乐，却意外地收到了很多优秀的作品。

这是2016年JS1k上传的作品，用几十行代码实现的一个3D旋转魔方： 




原代码在此：

function z(t, e) {
    return t? e? t.appendChild(e) : "width:"+t+"px;height:"+t+"px;position:absolute;" : document.createElement("div")
}

function w() {
    ++t==360&&(t=0, x=++x%3)
    for (i in m) 2 == m[i][s[x]] ? m[i][u][a] = r+s[x]+"(" + t + "deg)" : 0;
    c[u][a] = r+"3d(1,1,1," + t + "deg)", 
	requestAnimationFrame(w)
}
var a = "transform",
	p = "background-color:",
	y = a+"-style:preserve-3d;",
    u = "style",
    v = "cssText",
    B = z(),
    c = z(),
    t = x = 0,
    d, e, f, g, h, k, l, m = [], n, i, r="rotate", s = ["X","Y","Z"];

B[u][v] = "perspective:900px;"+z(600)+p+"#666";
c[u][v] = y + z(240) +"top:30%;left:30%", z(B, c), z(window.b, B);

for (l = 27; l--; z(c, f)) {
    f = z(), 
    f[u][v] = y + z(240), 
    f.X = g = l % 3, 
    f.Y = h = (l - g) % 9 / 3, 
    f.Z = k = ~~(l / 9), e = z(), 
    e[u][v] = y + z(80) +a+":translate3d(" + 80 * g + "px," + 80 * h + "px," + 80 * (k-1) + "px)";
    for (n = 6; n--; z(e, d)) 
    	d = z(), 
    	d[u][v] = y + z(72) + "border-radius:9px;border:4px solid #000;opacity:0.9;"+a+":"+r+"X(" + (4 > n ? 90 * n : 0) + "deg)"+r+"Y(" + (4 > n ? 0 : 4 == n ? -90 : 90) + "deg)translateZ(40px);"+p+ 
    	(0==n&&2==k?"#05C":1==n&&0==h?"#FD0":2==n&&0==k?"#0A6":3==n&&2==h?"#FFF":4==n&&0==g?"#F60":5==n&&2==g?"#C24":"#000");
    z(f, e), m.push(f)
}

w();

作品地址 http://js1k.com/2016-elemental/demo/2611